Island
Twelve.O.One Lyrics

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On an island I long to be
Gazing out upon the shining surface of the sea
I hear the sound of the ocean wave on wave
Crying, You who have turned away from home

Ascnam tar tuinn topur ndílenn dochum nÉirenn

Deus caeli ac terrae

Maris et fluminum
Deus solis ac lunae

On an island I long to live
Seabirds lament the coming of the winter wind
I hear the endless sound of sea on shore
Crying, You who have turned away from home

Deus super caelo et in caelo et sub caelo
Habet habitaculum erga caelum
Et terram et mare
Et omnia quae sunt in eis
Non separantur Pater
Et Filius et Spiritus Sanctus

On an island I long to be
Evening brings a whisper of the summer breeze
I hear the song of the ocean wave on wave
Crying, You who have turned away from home

Ascnam tar tuinn topur ndílenn dochum nÉirenn

Inspirat omnia
Vivificat omnia

Superat omnia
Suffulcit omnia

Overall Meaning

The lyrics of "Island" by Twelve.O.One speak of a yearning for the peace and serenity that can be found on an island. The singer longs to be away from the hustle and bustle of everyday life, looking out upon the vast expanse of the ocean. Throughout the song, we hear the sound of the waves crashing on the shore, a constant reminder of the power and beauty of nature. The lyrics also touch on themes of homesickness and the longing for a sense of belonging, with the repeated cry of "You who have turned away from home."

The song also incorporates Latin phrases and references to God and spirituality, adding to the sense of transcendence and connection with something larger than oneself. The phrase "Deus caeli ac terrae" (God of heaven and earth) and "Deus super caelo et in caelo et sub caelo" (God above heaven, in heaven, and beneath heaven) suggest a deep reverence for the divine and the natural world.

Overall, the lyrics of "Island" convey a sense of introspection and reverence for the beauty of the world around us. The desire to escape to an island and immerse oneself in nature is a universal feeling, and this song captures it beautifully.

Line by Line Meaning

On an island I long to be
The singer desires to be on a secluded island.

Gazing out upon the shining surface of the sea
The singer is looking at the beautiful waters of the ocean.

I hear the sound of the ocean wave on wave
The singer hears the calming sound of the waves as they crash on the shore.

Crying, You who have turned away from home
The ocean seems to be lamenting those who have left their homes.

Ascnam tar tuinn topur ndílenn dochum nÉirenn
A line in Irish Gaelic, which roughly translates to 'A melody on the waves, a signal to Ireland.'

Deus caeli ac terrae
Latin for 'God of heaven and earth.'

Maris et fluminum
Latin for 'of the sea and rivers.'

Deus solis ac lunae
Latin for 'God of the sun and moon.'

On an island I long to live
The singer desires to permanently reside on an island.

Seabirds lament the coming of the winter wind
Seabirds make mournful sounds anticipating the cold winter weather.

I hear the endless sound of sea on shore
The singer hears the constant sound of the ocean waves crashing on the beach.

Deus super caelo et in caelo et sub caelo
Latin for 'God above the heavens, in the heavens, and under the heavens.'

Habet habitaculum erga caelum
Latin for 'He dwells towards heaven.'

Et terram et mare
Latin for 'And the earth and sea.'

Et omnia quae sunt in eis
Latin for 'And everything that is in them.'

Non separantur Pater
Latin for 'The Father, Son, and Holy Spirit are not separated.'

Et Filius et Spiritus Sanctus
Latin for 'And the Son and the Holy Spirit.'

Evening brings a whisper of the summer breeze
The singer hears the gentle sound of the wind during the summer evenings.

I hear the song of the ocean wave on wave
The singer hears the melodies of the waves as they rise and fall.

Inspirat omnia
Latin for 'He inspires all things.'

Vivificat omnia
Latin for 'He gives life to all things.'

Superat omnia
Latin for 'He overcomes all things.'

Suffulcit omnia
Latin for 'He supports all things.'

Lyrics © Warner/Chappell Music, Inc.
Written by: MICHAEL PHILIP MCGLYNN

Lyrics Licensed & Provided by LyricFind

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Most interesting comments from YouTube:

Alex

3y↑4

The question from the episode is not who but which. As in "which is it": heavier or lighter?

Divide the 12 people into 3 groups of 4 people (G1, G2 and G3) and weigh G1 against G2 and G3, which is done by using the seesaw only twice.

If G1 is heavier than G2 and G3, then the answer to the question "which" is "heavier": 1 person on the island (in G1) is heavier than the other 11.

If G1 is heavier than G2, but weighs the same as G3, then 1 person (in G2) is lighter than the other 11.

If G1 and G2 weigh the same, then if G3 is heavier, the 12th person (in G3) is heavier. If G3 is lighter, then the 12th person (in G3) is lighter.

Finally, if G1 is lighter than G2, then if G1 is also lighter than G3, then the 12th person (in G1) is lighter. But if G1 and G3 weigh the same, then the 12th person (in G2) is heavier than the other 11.

The ink stained talon X

The ink stained talon X
I figured out the first teaser
You put three people on each side
If one side is different you know that they are within those six
If not they get of and the other six get on
You have one person get of from both sides until the balance changes
If the balance changes you know it’s one of those two
Then you have one guy sit on the seesaw with a guy from the other group that you know can’t be it
If it balances you know it was the other dude and if it tilts you know it’s him

Harsh Chahal

Anyone reading this please go to 3:29 and pause

we don't know if the person is heavy or light lets choose No. 5 heavy just to go through this. Starting with the riddle it could be any one of 1,2,3,4,5,6,7,8,9,10,11 or 12.

Step 1- See-saw tilts towards right. (no.5 heavy). Which proves 9,10,11 and 12 are same weight can be eliminated. So the person must be any one of 1,2,3,4,5,6,7 or 8.

Step 2- See-saw tilts towards left (no. 5 heavy). which proves 6,7,8 and 12 are the same weight so can be eliminated. we already determined 12 in the fist step so additionally we know 6,7 and 8 are also same weight. So the person must be any one of 1,2,34 or 5.

Step 3- See- saw doesn't tilt (no. 5 is not there). which proves the people on the see-saw are same weight so no. 3,7,9,10,1,4,6 and 12 can be eliminated.
From all three steps we get to know 1,3,4,6,7,8,9,10,11 and 12 are the same weight.
So we are are still left with no. 2 and no.5. which never got eliminated and we will never know which one of them weigh differently.

you are absolutely right about the configuration but you will always be left with 2 people not one. I beg you to prove me wrong cuz I want to have a solution.

Søren Hougaard Rasmussen

4y↑1

Find the 27th permutations first. Group them so you they are paired in reverse (left becomes right). Note that the three permutations CCC, LLL and RRR are not used. Now the only thing you have to make sure of, is that there can only sit four people on one side. Note that a C will always stay at the same position. Start by picking four permutations witch start on the left and assign them to the first four people, make sure out of the 8 possible pairs that you pick ones with different places for the second and third letter as evenly as possible:

1: LLR RRL
2: LRR RLL

3: LCL RCR
4: LCC RCC

The next four are given, it is those that begin with R:

5: RRC LLC
6: RCL LCR
7: RLR LRL
8: RLC LRC

Now look at you distribution of the three weightings:

L C R

1234 5678

178 346 25

36 458 127

Now distribute the last four pairs accordingly:

a: CCR CCL
b: CRC CLC
c: CRL CLR
d: CLL CRR

L C R
1234 abcd 5678
178d 346a 25bc
36cd 458b 127a

Notice how easy it is to switch the last four pairs around so they match up. CCR/CCL can be changed if there are too many on the right side and too few on the left in the third iteration and it doesn't affect any of the others.

Lastly see that my solution is different than the guys in the videos, there are more ways to to it, but they all have the same principle.

Avenger_ a a win

@Alesio Syou only need to figure out if he's lighter or heavier
0:43 'one of them is slightly lighter or heavier you must figure out which'
you don't need to know who the guy is; you just need to figure out if he's lighter or heavier

12 men A B C D E F G H I J K L
1st try: A B C vs. D E F
if it's balance (let's call this outcome V) then we know that the abnormal man is one of
(G H I J K L) then we compare (A B C D E F) with (G H I J K L)
(after outcome V)2nd try: (A B C D E F) vs. (G H I J K L)
if (G H I J K L) goes up then the man with the different weight is lighter
if (G H I J K L) was lower then that means that the odd man has a higher weight
* after the first try if the seesaw wasn't balanced (let's call this outcome W) then we know that the odd man is in (A B C D E F)
then we compare (A B C D E F) with (G H I J K L)
(if first try outcome W) 2nd try: (A B C D E F) vs. (G H I J K L)
if (A B C D E F) was lower then that means that the odd man has a higher weight
if (A B C D E F) goes up then the man with the different weight is lighter

All comments from YouTube:

Das

4y↑98

Thanks for satisfying my curiosity in the middle of a Brooklyn 99 binge watch session! Your solution is so elegant.

Kenny Sabellano

4y↑269

Rosa’s solution is still the best

Salvador Arreola Rodriguez

3y↑1

No...

Adamphibia Kalboonchuy

3y↑63

"You use the seesaw to press down on their necks until fatty confesses."

OZDB

3y↑16

Incorrect...and disturbing!

pierrealexguev

4y↑281

Somebody gives that men a pair of Beyonce tickets.

Ali HN

5y↑87

I have not been able to sleep in peace for the past year and a half! Thanks for clearing this up for me😅

Squidy

3y↑5

I'm usually not so into puzzles, but this one was really fun to figure out for myself. I actually got something different, but in my answer it isn't the same 3 actions every time. Still a really fun puzzle and a great explanation!

LifeProjX

3y↑2

Thanks! It was a good puzzle. Thanks for watching

Guidotie

What was your solution?

Squidy

@Guidotie @Guidotie first test: you weigh 1,2,3,4 against 5,6,7,8. If they're equal then:
you weigh 1,9 against 10,11. If they're equal then 12 is the answer. If not, write down which side was heavier. Then you weigh 10 against 11. If they're equal, then 9 is the odd one out. If they're not equal, and 10,11 were heavier than 1,9, then the heavier one is the answer. If 10,11 were lighter than 1,9, the lighter one is the answer.
Now: if the first weighing tips to one side, write down which side it tipped to. For the example, let's say 1,2,3,4 are heavier. Then, Put on each side of the scale two people from one side and one from the other. let's say, 1,2,5 against 3,4,6. If it doesn't tip, that means 7 or 8 are the culprit. Because they were on the lighter side in measurement 1, you weigh them against each other and the lighter one is the culprit. Now, if measurement 2 tips to one side, let's say to 1,2,5, that means that either 1 or 2 are making that side heavier, or that 6 is making the other side lighter (based on the fact that 1,2,3,4 tipped down on measurement 1). So you measure 1 against 2, and the heavier one is who you're looking for. If it's equal, the answer is number 6. Ok that's it

I'llEatThat

@Squidy why is "the lighter one" the culprit, when it could be heavier?

Squidy

@I'llEatThat if the scale tips to one side, then one of them is the culprit. Now, we know this individual was on the lighter side of the scale in the previous measurement, meaning that whoever the culprit is is lighter than the rest. That's why if the scale tips, it's because one of the guys is lighter than the rest, meaning he is on the lighter side of the scale.

10 More Replies...

Justin Rosales ⚡️Practice Your Passion

2y↑2

Brilliant. Thanks for running through a couple of examples. Also, installing a Whiteboard in your personal studio, so legit. I might need to do that

Llain 00

4y↑62

It’s on an island, all 12 men are placed in the water surrounding the island. All 12 men then exhale fully causing them to sink, the one that doesn’t sink at the same rate is the islander of a different weight.

Aaryan

4y↑2

Holy shit.

aryan chauhan

4y↑14

nah wont work. buoyancy depends on shape as well.

darrell5703

Muscle density and fattiness of the men would determine buoyancy as well. This is coming from a man who took swimming lessons in his 30’s and came to find out that I can’t float because I’m too “dense”.

Sir Laughsalot

@aryan chauhan If the object displaces an amount of water equal to its own weight, the buoyant force acting on it will be equal to gravity—and the object will float. But, if the object weighs more than the water it displaces, the buoyant force acting on it will be less than gravity, and it will sink.

A giant ass ship will sink faster when the air is gone, just like a man will sink faster or slower if they are heavier or lighter.

Trebor Heminway

You are not measuring displacement, your measuring density. To calculate the weight, you would need to know volume! You could have a lighter man, that's more dense because he's small.

Alex

3y↑4

Parth khaladkar

I was looking for this comment! The wording in the show IS sort of unclear.

Adamphibia Kalboonchuy

3y↑17

Rosa: One guy is slightly heavier. There's a seesaw. You use the seesaw to press down on their necks until fatty confesses.
Islander #4: (screams) It was me! I'm the fatter one! You got me!

LifeProjX

3y↑3

haha, really the best way to solve the problem

Geir Ånadal

A bit late here, but I only saw this episode a few days ago, but this is the solution I came up with during the episode. You put 6x6 on the see-saw. It will tilt either right og left. then you take off one person on each side until the see-saw levels. Then you weigh the 2 last persons to leave the see-saw against another person. One will be equal the other will be either lighter or heavier.

jylounen

3y↑1

That's more than 3 uses of the seesaw

TheVillainOfTheYear

4y↑3

Holt never defined what constitutes a use. If you define "use" as number of times you put men on the seesaw, then there is a simpler solution that will always yield the correct result:

Use 1: start with six on each side. In this configuration the seesaw will be tilted because the weight will be uneven. Have one islander from each side get off. If the seesaw remains tilted, those two were the same. Remove one more from each side. Repeat until the weight equalizes when two men get off. One of those two is the odd man. Label those two A and B.

Use 2: Weigh man A against any other man but B. If they are balanced, B is the odd man out. If they are not balanced, A is.

Use 3 is a red herring.

Søren Hougaard Rasmussen

4y↑1

Use is the number of times the weight is being tested, where is no reason to think it is only when persons climb on it.

Matthew Deroche

5y↑3

While I did come up with a way to solve it, it was nowhere near this simple. Very well done!

Julie and Tom Kenyon

See saws react to torque, not weight. You need a hanging balance, not a see-saw. If two men with identical weight got on opposite sides, it's unlikely the see-saw would balance unless their centers of mass were exactly the same distance from the fulcrum.

Thomas Jensen

Thanks for making it easy to understand. I just subbed. I saw the problem on the show as well.

LifeProjX

Thanks for the sub!

Guillermo Tinoco

4y↑6

This might be me not understanding the premise clearly cause of language barrier, but i though in the way captain holt phrased it, he only asked to know if the person was ligther or heavier, not who the person was.

Glad to know the right answer finally.

pewpewandrew

he asked which

John McLaughlin

3y↑1

You are correct. Your understanding of English is better than anyone else's on here by the looks of it.

I'llEatThat

He did, which is what most of these responses don't acknowledge, they just assume in step two that you can say that 7/8 is heavier- when it could be that it's the other number being lighter

The ink stained talon X

Richard Thompson

3y↑11

"Can you work out which is heavier or lighter by only using the see saw 3 times?"

"Sure thing, just let me use it another 72 times first"

Escadrila

2y↑3

Right,makes no sense??
Just because he chooses number and it works with his algorithm.
We cant assume that he is lighter or heavier and then say yes it will go there and there.even if the first try the scale is uneven it still means that there are 8 possible answers,because he can be either heavier or lighter.
Wich group to chose than.

LoH Bros

What if the real test was comprehension. Holt doesn't ask you to figure out 'who AND whether they're lighter or heavier' as is on the whiteboard. He simply says. One is heavier or lighter, you must figure out which. As in, you only needed to figure out whether the odd man out is heavier or lighter. Which is easy, but leaves a lot of people focusing on the wrong thing and doing a bunch of extra and unnecessary work because they didn't take the time to understand the ask :)

LifeProjX

50w↑1

possibly for the show. but the problem is a pretty famous math problem that's why I went with the famous math problem solution.

John McLaughlin

The problem, as stated, does not say you have to identify the individual. It asks you to determine whether the exceptional individual is lighter or heavier. That's all.
You only need two uses of the see saw to solve this problem.
1. Six on one side, six on the other. Take the heavy six and....
2. spilt the heavy six in half, three on each side. Balanced = Lighter. Unbalanced = Heavier.

Harsh Chahal

LifeProjX

It really good thought, but there is more information that you are forgetting. the 2 and 5 swap from being on the same side of the scale to being on opposite sides of the scale. if I take everyone off the scale except the 2 and 5 (for a visualization) for the 2 to be the correct answer it would have to switch from being light in weigh 1 to heavy in weigh 2 (same with everyone still on the scale). I didn't use an elimination method to solve this, but if I did I can eliminate #2 because it can't change weight. great thought tho!

Kareem Hijazi

2 groups of 6 (A&B), note which group is heavier/lighter (for example group A is heavier).
Use your remaining 2 trials to weigh each group of six against each other (3x3) and find out which group of 6 (A or B) includes the odd man
if group A includes the man then he is heavier and vice versa :)

LifeProjX

5y↑1

In 2 groups of 6 if the scale tilts down on the right you won't know if there is a heavy person on the right or a light person on the left.

Dina Issa

@LifeProjX Shit. That's what I didn't think of!

Jared W.

Yes because actual mind twisters are this complex, complex enough that you would need a giant formula to solve it. There is no way that they expected thier standard viewer to figure this out.

0123Dayan

I solved it with a simple method of 5-5-2 and only 3 uses of the scale.

Shadowdante110

Another way is to split the 12 people in 2 groups.
1st measure, 6 on one side 6 one the other, one side with be heavier or lighter
2nd time, take the group with the weight disparent person, split that group in half, 3 to 3, reweight them.
3rd time. Now you will be down to 3 people. take 2 of those people, split them into two groups. put them on the scale. Now you have one person on each side of the scale, and one person off to the side. Now, no matter what you know which is weight disparent. Because if the scale comes out equal you know the person off to the side has the off weight, or if they are on the scale, you can easily see which one it is.

LifeProjX

if you do 6v6 you won't know if there is a heavy person on one side or a light person on the other.

Shadowdante110

@LifeProjX Oh right. I forgot that we didnt know if it was heavier or lighter. Thank you.

Zmanj413

Could you do 5 on left 5 on right, if it doesn’t tilt then 1v1. If it does tilt put 2 and 2 from the side that tilted, if it’s balanced it’s the one left out otherwise put the two that tilted in a 1v1 you’ve found your odd one

Sam Simmonds

5y↑32

How do you know who to put on the see-saw for the second and third use? Like the video by the way 👍

Bruno Hirata

5y↑1

You assign a number from 1 to 12 for each person beforehand. This way you'll always know who to weight at a given time.

TwistedCupid

4y↑2

@Bruno Hirata okay, so I did that and there are some numbers that come up the same with others. So do we have to make sure that each number is not paired up with another number that it was paired up with before? How do we know which group goes to which side and how to mix them up question mark you see, I put it in an order, of one two three four five six seven eight nine 10 11 12, and I had one two three four on the left side of the Seesaw, and I had 5 6 7 8 on the right side of the Seesaw, and I had nine 10 11 12 on the middle. However, when I put 9 7 5 10 on one side of the Seesaw and 1 4 8 12 on the other side of the Seesaw and the rest in the middle, and then of course another combination... Some numbers came out with the same combo. Some numbers had RLC twice. So now I'm even more mixed up or am I overthinking this?

pannja123

4y↑2

@TwistedCupid You make the LCR arrangements first, then put the people on or off the seasaw accordingly.

Missy

Only need to find out if they r lighter or heavier, so could put 1st set of 4 on with 2nd set of 4 and if its uneven(L) then take one side off and put the 3rd set of 4 on if it stays the same you know the person is heavier, if it's even put 2nd 4 back on with the 3rd 4 and depending on which side it goes to you know whether heavier or lighter

Shankar Roy

I sort of understand it... so thanks...
Can you do the solution for the BONE problem? (B99 fans will get the reference)

LifeProjX

Haha, already working on it. I just have to have all my t's crossed and my i's dotted before I disagree with vsauce and everyone else on the internet.

LifeProjX

2y↑3

Its Official! You have all bullied me enough to force me to make another video on this Puzzle haha. I will post a video explaining the puzzle completely (including the algorithm for sorting the islanders into their positions in the chart) Not only that, but I will break a world record for the most number of islanders ever solved for which hopefully will only stand for a short period of time as I hope one of you will break my world record shortly after! Video Coming Soon!

owaishere

Its a riddle, not a maths problem.

You put all 12 on the see saw. Make sure they get off one by one, alternating sides. Then wait til it balances and the last pair that jumped off will be the odd one out

geoffrey calligan

5y↑1

To complicated the first use you should do 6 vs 6 and when the men are getting off have 1 man from each side step off at a time until the seesaw is balanced then take the 2 men who stepped off just before the seesaw balanced and 1 man you now know weighs the same as the others and use him to weigh against the last 2 men to step off one at a time you 1vs1 and 1vs1

LifeProjX

I thought of server "work arounds" while solving the puzzle. I could argue that each time someone stepped off that would be considered a use. Since I solved it I have done a lot of research of the problem and it is quite famous. also known as the 12 marble problem or the 12 coin problem. Understanding the intention of the problem I know its not just a word play game and does have a mathematical solution.

TheVillainOfTheYear

@LifeProjX do you really think a riddle that can be asked and apparently explained over dinner would require a chalk board?

LifeProjX

TheVillainOfTheYear this riddle probably would.

Ben Cheevers

I found an internet answer that was absolutely wrong, I thought this was a tough puzzle, this was great!

LifeProjX

thanks! Ive got a new video coming that really dissects this problem and allows you to solve for any number if islanders.

Jonatas Sousa

4y↑11

I don't know why Holt discarded Santiago's solution as I came to the same:

1-weigh 6 vs 6, then take the group of 6 that tilts up or down
2-weigh 3 vs 3 and do the same.
3- here you have just 3 people, weigh any 2 of them, even If It doesn't tilt you'l know the person outside is the discrepant one.

Why is this incorrect?

LifeProjX

4y↑20

Jonatas Sousa it’s because you won’t know if there is a light person on one side or a heavy person on the other side. A 6v6 only works if you know whether the islander is heavy or light before you start

Håkon Skaanes

4y↑2

2-weigh have 2 outcomes: tilt or no tilt. Your sulusion does not factor in a non tilt in weigh nr 2

Annabelle Yang

4y↑1

Great solution! Could you link the video that explains how you got it please?

LifeProjX

thanks! you can check out the explanation here https://youtu.be/pwx1ytZG59A

Missy

Mr Tiny

I have kinda simpler solution. Just separate it to 3 group 1234, 5678, abcd. 1st situation 1234 and 5678 is balanced, now this one is too easy so i won't talk about it. If you can't do it yourself then just give up. 2nd situation they are not balanced then I will take 3 from the lighter side away (I suppose it is 678), then put 3 from the heavier size to it so we will have 5234. Now I take 3 from the other group and add to the heavier side and we will have 1bcd and 5234. Now it's quite easy but need focusing. 1st case the seesaw doesn't change, it means either 1 is heavier or 5 is lighter. Just try one of them with the regular one. 2nd case the seesaw is balanced then there is a lighter one in 678 (it was in the lighter side). Just weight 2 of them and we'll find out. Last case the seesaw change side, it means one in 234 is heavier than the regular one. Voila.

Chencob B

Split the group into sets of 3 (4 people per set) group a and b go first. If one side is heavier then that group has the heavier person, if the seesaw is equal then it must be group c. Take the group that is heavier and split them into two, repeat process, which ever side is heavier take them and split the two again and then you have the answer with the third use. Would this work?

Sgt Pluck

46w

Maybe the other group has a lighter person......

Marc Millar

how has Holt not just googled it like me before?

Asad Khan

3y↑1

This is actually a really popular Graph Theory problem. Computer Science or Mathematics people should know the solution.

LifeProjX

Not sure what graph theory is, but it sounds cool. might have to spend some time looking into it.

Asad Khan

3y↑1

@LifeProjX If you love puzzle solving, you'll definitely love graph theory. You should start with the Konigsberg bridge problem. This problem was the birth of graph theory. Maybe you can make videos about more graph theory problems!

Edit: Might wanna start with this video.
https://www.youtube.com/watch?v=nZwSo4vfw6c

CharlieWinters

4y↑3

How did you manage to get the chart to determine weather the islander is heavy or light?
*by that I mean all the
rcl =light
Cll =heavy
rcc =light

LifeProjX

https://youtu.be/pwx1ytZG59A

TwistedCupid

4y↑2

What formula did you use to place which guy on which side? Some combinations came up for more than one guy.

Søren Hougaard Rasmussen

4y↑1

Ega Chen

hi, very cool and understood! can you share the algorithm (or way of thinking) for you figure out the solution here.

LifeProjX

Yea, have been planning to for a while. I'll try soon.

Assumption is the mother Of all fuck-ups

Take all 12 men put 6 on see saw the other 6 on the other end which ever side is lighter or heavier you keep that group kill the other 6. Next weigh divide the 6 into two groups of 3 repeat process kill the 3 that side which is lighter or heavier now using see saw last time you have 1 sit on each side while 1 waits on the end if they weight the same the see saw won’t move and that means guy on side is the one you’re looking for if one side is lighter or heavier you found the guy ….🙌

jmahoney1979

This seems easier
1st 6 on each side
2nd 3 on each side (split the heavy group from round 1)
3rd weigh 1 on each side from the last 3 remaining.
A. If 3rd round seesaw is flat, the man not on the seesaw is heaviest. If the heaviest usvon the seesaw, the seesaw will show who's heaviest

Ramón Parellada Martín

I thought that too, but it doesn't work, since it can be heavier or lighter.

Troll King

3y↑2

How bout 6v6, then 3v3 then leave a guy out when doing 1v1. If they balance out, then guy left out has different weight. If it doesnt, ask the rest if the guys to lift the last 3 guys.

Evan Nguyen

You have to know if the person is heavier or lighter, if u do 6v6 you get no information with that use, you just know one person is different which you already know

Rudyolf Schiermeister

4y↑23

Im surprised the creator of brooklyn 99 didn't comment on this

LifeProjX

4y↑9

I don't know if I could handle knowing that a creator of Brooklyn 99 watched a video that I made. I am clearly not cool enough for something like that.

Austin Heinbuch

I’ve seen this riddle elsewhere, they didn’t create it.

Rafael Lima

the problem with your solution is that there is no rational behind it. it is just brute force

im not sure if it is possible to work it rationally as slit and conquer or something...
but your solution only works if you have paper and pen and you are able to map everysingle possible outcome before

so if you were in an oral evaluation, or if you were in the island itself you would be able to do that [even if you know you answer] you would need to memorize all this 24 outcomes and the 3 seasaw configurations

LifeProjX

I know, unfortunately I have been talked into making a 3rd video about this problem. All the prep work is done and all I need to do is film it. I promise you will have no questions after the next video. I am going to explain how to solve yourself and by the end I will work through a solution to 1093 islanders in 7 weighs.

julia -

4y↑1

ok so hear me out- assuming that the odd one out doesn’t know what everyone else weighs then you just ask them one by one to tell them their weight and the odd one reveals himself

LifeProjX

4y↑1

I love the way your brain works. Im not sure thats the idea behind the riddle, but definitely the most creative reply I've had.

0123Dayan

I found a very much easier solution with a 5-5-2 method, and using the scale only 3 times. :)

LifeProjX

Id love to hear it

Alicia Raphaela

Como eu queria que tivesse em português, pelo menos legendado...

LifeProjX

Vou colocá-lo no google tradutor e adicioná-lo para você. Vou tentar fazer isso até o final da semana para você.

loz

4y↑3

At first i was like they stupid it’s 6 vs 6 and then the heaviest you split into 3 vs 3 and then you do 1 vs 1 and if it’s equal it’s the one you left out if there’s one leaning away it the heaviest and then I realised it’s heavier OR lighter and I was like arghhgg 😂😂

Anand Srivastava

4y↑1

Same bro😂

CT 481

4y↑1

I mean you could start with 4 vs 4 and leave 4 out and if the seesaw stays the same then it’s the left out group that’s the heaviest or one of the two groups compared. Then you can separate the 4 into a 2 vs 2 and then a 1 vs 1 but idk if that’s right but I can’t see how it isn’t

loz

4y↑2

CT 481 because it not heaviest of lightest, it’s just a different weight, that’s where I was confused

Cori Tucker-Toone

thx, i think a lot of people don't know the solution! but i did. i came across this in recommendations! and i wanted to see if we had the same answer! my answer was (i have not watched the video yet) is: there is a seesaw, you put the guy who either ways less or more on the seesaw, and another islander on the other end. depending on if he goes up or down, is how much he ways. edit: he never said you had to use ALL of the people on the island

LifeProjX

3y↑1

its a good thought. I don't think you know who the heavy/light person is, but that is definitely some creative thinking!

Cori Tucker-Toone

@LifeProjX thanks!

I'llEatThat

Why have you grouped them into 4? The least most common nominal figure of all the numbers involved?

GGGalaxies

What I did was put 6 on one side and 6 on the other, one side weighs more so the first 6 are taken out, the put the second 6 in 2 groups of three and do the same, the remove one person from the now 3 then use the seesaw again, if they weigh the same then it's the person taken out if not then I guess this is straight forward. So amy was onto something before Holt told her it wouldn't work

LifeProjX

4y↑1

if you do a 6v6 you won't know whether the person is heavy on the right or light on the left.

Andrew Boryszewski

How did you form the matrix of XXX? Why didn't you put LCX in the left column, for instance?

LifeProjX

check out the other video I made on the problem. it explains it better. https://youtu.be/pwx1ytZG59A

SashaZtoriez

“Just get these islanders off this nightmare weight obsessed island!”

LifeProjX

poor islanders. haha

Aryamann Khare

Why not apply the Monty hall problem solution to this puzzle? I mean divide the 12 islanders into 3 groups of 4, and apply the same logic which is applied in the Monty Hall problem.

LifeProjX

Im going to have to put some thought into that, but on the surface it seems like you are just increasing the odds of finding the group the person is in. maybe elaborate and I can think on it a little more.

gumibear131313

This is so complicated.... I got a completely different solution but its probably wrong lol

Avenger_ a a win

if u put 3 v 3 on the first move
you can eliminate 6
if it's balanced then the odd one is withing the 6 that haven't been weighed
if it's not balanced then the odd one is one of the 6 that have been weighed

Alesio S

Is the odd one the heavier or the lighter?

Avenger_ a a win

@Alesio S then you can place the 6 normals on one side and the other 6 the ones with the odd fella on the other side
if the group with the odd one leans down then the odd one is heavier
if it leans up the the odd one is lighter

Alesio S

@Avenger_ a a win it doesn't make any sense. In just 3 tries you will never get the heavier or lighter guy with your theory

Avenger_ a a win

Alesio S

@Avenger_ a a win One is lighter or heavier, you must figure out which. So you have to know which person it is. And think about this, would be harder to know who the person is than knowing who's heavier or lighter, so, by logic, the "Creator" of this problem would do it the as harder as he can.

Andom Neraio

Wish u had explained the solution with a test run rather than proving you know the outcome of the tilt for every number depending on that number being light or heavy.

sakgamer XD

THANKS !! !! !! !! !! !! !!

M.I. Orko

Use the Seesaw 6 vs 6, whichever team cones heavier will do 3 vs 3 then again 1 vs 1. If the weight is the same then the other guy is the heavy fucker and if the heavy fucker is one of the 1 vs 1 contestant then you will see him right away. Its simple

LifeProjX

4y↑1

You won't know if the person is heavy on the one side or light on the other if you do a 6v6

M.I. Orko

@LifeProjX You can because the question is hypothetical so size of the seesaw, speed, momentum, gravity etc wont kick in. You can do 11 vs 1 and it will show the perfect result even thought its just a seesaw. So because 11 of them are the same size and 1 of them is different so there will be a difference in weight every time. We just need to divide the difference 2 more times to get the answer

amir

This puzzle broke my brain

Framu

3y↑1

I have come up with a solution in which you do 4 vs 4, 2 vs 2, and 1 vs 1. I would not say that it is simpler but it is curious.

Framu

3y↑1

Well in the second use it is 2 VS. 2 or 3 VS. 3 depending on what happened in the first use.

will

That one works if we know whether or not the man is lighter or heavier, but in this case, we don't know. Ergo, for the first 4v4 weighing, if the see saw tilts, it's impossible to know which of the 4 to pick from to do the 2v2 weighing. Ergo, the solution in the video is necessary.

Framu

Will Leet No, my solution works even if you don't know if it is heavier or lighter

Alex Bachtsevanos

4y↑1

What if you split them into 4 teams of 3 and then compare a pair . if the see-saw is stable take the remaining 2 otherwise continue with the ones you have .Then you take one of the imbalanced teams and compare them to a balanced .If stable ,proceed with the other one , otherwise cotinue with the one you have . By the way the see saw leans you will also know if the man is lighter or heavier . At the and you take 2 of the men on the remaining heavier or lighter team and put them on the see-saw with one other man of the previous stable groups each . If it remains stable then the 3rd man that we didn't weigh is the odd one , otherwise you will get your awnser . @LifeProjX

Alex Bachtsevanos

there is just one flaw with the last measure of the final 3 who were the odd one all alonge . If the see saw is balanced then he 3rd one is the odd one , but what if it didn't balance ? Then you wouldnt know if the odd one was heavier or lighter . Please help !

Alesio S

4y↑2

I know the solution:

You give a big bunch of food to one of them letting the others starve. No need to use the see-saw, that guy is gonna be the heavier! ha!

LifeProjX

4y↑1

I like the way your brain works.

andrew baggs

Ha ha, I figured it out in 6 minutes; with a couple glasses of fine red wine. This is what simple is..1st measure 3 and 3..balanced, set all aside. Unbalanced; you divide into 2 groups. 2nd measure; you take 3 of the balanced group vs 3 of the unbalanced, the unbalanced group will go up or down (heavy/ light!) or stay balanced. If balanced set aside. If unbalanced

andrew baggs

You now have 3 unbalanced people left but you know that 1 is heavier or lighter than the others from the previous measurement now Measure 2 on the see saw and you have your answer .. if balanced the loner is the heavy/lighter one or the one heavier or lighter on the see saw based on the previous measurement is the odd man out! Baaaam!

Musawir Mehfuz

So If I understood correctly the answer is person 11?

Tyler the creator stan

4v4 if it is equal Eliminate those Islanders as suspects than work in the next four 1v1 and 1v1 you will than see who the person is and if they are lighter or Heavier if the original 8 are the Culprits take the side that is heavier or lighter and Repeat the steps

Alesio S

How do you know which one is the heavier or the lighter? That's the problem here. If you chose the heavier side and then 2vs2 is the same weight you will know than the other 4 is the odd side. But you wasted all the bullets

J Colin Mizia

While this does work, I feel like it misses the spirit of the problem of finding a step by step algorithm.

I have worked out my own algorithm that does work, but it’s a touch complicated. However, I would argue that it is “simpler” as it takes no preliminary work.

LifeProjX

I have an algorithm that I use to sort sort the information. I haven't made a video explaining it, but I do have a more in-depth video explaining the solution. https://youtu.be/pwx1ytZG59A

Timmy Johnson

Can I try.
Let's rephrase the question.
A butcher stands 6'4". What does he weigh? Answer: meat.
Therefore; 12 men on an island. 11 weigh the same. One weighs whatever they are bringing in that day. Three tries, you are either more or less.
Tomorrow, 11 men are weighing sand. Next day meat. Dugh!

Joe Derrett

I do it in 2 uses of the seesaw. Am I missing something?

split the 12 into 2 groups of 6 (group A and group B). split group A into 2 groups of 3 and place onto seesaw.

If balanced
The odd person is in group B. Measure A v B if B weighs the most the odd person is heavier. If A weighs down odd person is lighter.

If unbalanced odd person is in A. Weigh A v B. If A weighs down odd person is heavier. If B weighs down odd person is in lighter. 2 uses. 🤷‍♂️

Alp Eren Özdemir

how are you gonna find out who is lighter or heavier ?

Alp Eren Özdemir

I mean lets just say number 8 is the odd one how are you gonna figure it out

Ben

Its only one method of the problem. Still there is a million way to do it.

aljaž bruner

5y↑1

The main question is just to find out if the twelfth man is heavier or lighter not who this man is. The solution is quite simple. You divide them into four groups of three. Then you weigh two groups together on the see saw and you spend two weighings, this gives one measurement that shows balance and one that dose not. You have to remember wher did the see saw leaned with the groups thet were not balanced. Then you take on of the groups and sit it with a one of the groups that showed balance. If thay are agen in balance you have to look at the resolt of the previous weighing if they are not you can see if the twelfth man is heavier or lighter as the seesaw will tilt up or down agenst the weight of the calibrated group. After three weighings we determin if the twelfth man is heavier or lighter.

Iversia

But you still don’t really know who it is. Your choosing whoever islander you want and assume that he could be light or heavy. This video gives me all the probability of every islander if he is light or heavier, but still I have no idea who is truly the one who different from all other islanders, and whether he was heavier or lighter. I’m still confused 😅.

LifeProjX

the solution gives you the ability to identify the islander no matter who it is. If you picked the islander and whether they are heavy our light and didn't tell me who it was or whether they were heavy or light. I could ask you at each stage which way the scale would tilt and after all 3 stages I would have the answer.

tinybitofchaos

There's actually a much easier way to do it lol without all these lefts and rights

Stephan Wilson

I think the most simple solution can be done in two moves 3 groups of four labeled ABC first move AB
Second move AC
Then you dont need anymore moves since you only need to know if its light or heavy.
On the first move AB if A is less then B and AC are the same it means the answer is heavy. If AB is equal then you know A is the same weight and you look to see if C goes up or down to find out if light or heavy. If A is greater then B and AC are the same then then the answer is light.

MD

it does not work… say a man in group B is heavy, then test AB, B sinks; then test AC will be level; so you know B is heavy, however then you have 4 men in group B to test for the third attempt - not possible to differentiate who is heavy in group B

Dennis Cholo

i could see if the first 8 were even then the odd one out is 9 10 11 12 but what is the reason for 1259 34 10 11? how did you come to this set of numbers? or the next set? let me know and thanks.

LifeProjX

Here is my video showing how to get the numbers https://youtu.be/pwx1ytZG59A

LifeProjX

I have a better video coming out showing a more complete solution

Sumo Shark

I don't think this is the solution seems a bit too complex. The riddle is from a light hearted TV show, this seems a bit too much. In truth you could interprete the riddle as "figure out if 1 person is lighter or heavier", you don't have to work out who that person is, just if they are lighter or heavier. Which is very easy to do. Will say I really like how you did it though.

The one and only jazz The autobot

4y↑1

Take 3 groups of four people each of the four people split up into two and then get on opposite ends of the seesaw if it balances out then do it again 2 more times

DeathReaper 969

But im still confused, cause doesnt that mean you could say islander 9 is heavier or 6 is lighter etc, like is there a fixed anwser who it is and what they are or can it basically be anyone being anything if that makes any sense, im bad at explaning things lol

LifeProjX

5y↑1

It's a layout that answers the question no matter who it is and whether they are heavier or lighter. because the information is laid out symmetrically if person 9 is heavy it will give the symmetrical opposite answer as if he were light and that's what makes the chart work. Im not sure if that answers your question. I wasn't 100% sure what you were asking

DeathReaper 969

@LifeProjX thank you for anwsering. I understand the chart but from what i understand there isnt a fixed anwser. So if i would tell this math problem to a friend there isnt a anwser i could give them as like "its islander 6, and he is heavier". Because from what i understand from the video it can be any of them.

LifeProjX

5y↑1

DeathReaper 969 correct, it could be any islander. That’s what makes the puzzle hard. You need to find a solution that works no matter who the islander is

DeathReaper 969

@LifeProjX oke cool, thanks for helping out man, i really appreciatie it. Keep it up mate✌️

Ved Arovski

3y↑1

I can do it by just weighing them twice. First, weigh them 6vs6. Choose heavier team. Split them into two groups. If they have equal weights then the guy was lighter. If they do not have equal weights then he was heavier.

If the guy was heavier, then the heavier 6 have that guy. When we split that group they won't be equally weight if the guy is in one of the groups.

If the guy was lighter, then heavier 6 won't have the guy. So, when they are split into 2 groups they will have equal weights.

shrill burger

I have a solution but I need to know what is a utulisation

Mikiyas Tesfaye

3y↑3

6 vs 6, take the heavy 6 and split into two
3 vs 3, take the heavy 3 and do
1 vs 1. If tilt left, guy on left. If tilt right, guy on right. If equal, guy not put on the see saw.

Legion

3y↑5

But you don't know if they're heavier or lighter, so no matter which way it tilts, it could be either. It could go up because that guy is heavier, but it could also go up because the opposite guy is ligher.

daaaaaangh

use 1: six people against six people
use 2: use the heavier side from use 1 and split them in 3 against 3
use 3: weigh two people from the heavier side from use 2.
conclusion: when te seesaw shows that one man is heavier than that he is the odd one out, if the people from ion the seedsaw weigh the same than the third man from that group is it.

Søren Hougaard Rasmussen

4y↑1

The person can be heavier or lighter. Man so many people are not listening to the rules given from the puzzle. Your method are not a guarantee.

Rebi Reh

Do the Doors and the price thing

LifeProjX

Ill try and finish the video next week.

Youssef Zidouh

i think the riddle just asks the one with different weight not if he is lighter or heavier you just wanted to make it more complex and as u just said its super easy and u don't have to get mathematical for it am not criticizing just pointing that out the part you did is for math geeks

LifeProjX

Youssef Zidouh check out the original clip. https://youtu.be/UfXXTtJG15o

Vinicius Resende

SOMEONE PLEASE TELL ME WHAT IS THIS EPISODE AND SERIES ???????

LifeProjX

Brooklyn Nine-Nine season 2 episode 18

Dakota Sirmons

5y↑1

You're over thinking it. It's a word play riddle. He said you have to figure out if the 12th person is "Lighter or Heavier". He never said you had to figure out who the 12th person was. So all you have to do is put person 12 on the seesaw and have someone else sit on the other side and see how it tilts, boom, your done. The 3 uses of the seesaw and everything else is just in there to confuse you and make you over think it.

LifeProjX

The problem with that is that Holt never specifies which islander it is. He says " There are 12 men on an Island. 11 of them weight exactly the same amount, but one of them is slightly lighter or heavier. You must figure our which." he does not say that it is the 12th person, just that it is one of the 12 people. To figure out whether the odd person is heavier or lighter you must also determine which islander it is.

LifeProjX

Also Ted-Ed also did a solution to this problem, my solution is just much simpler.

geoffrey calligan

Right and wrong the key is the number of time you can use the seesaw you can use it 3 times if the first time you use it you have 1 man at a time from each side step off it is easy

Ediz Chakarto

“There are 12 men on an island. 11 weigh exactly the same amount, but one of them is slightly lighter or heavier. You must figure out which. The island has no scales, but there is a see-saw. You can only use it three times.”. This is a riddle. Not a maths question. It is about the way it is worded. If you listen to carefully to the question, when Holt states; “you must figure out which” the question is referring to whether the person who weighs differently is lighter or heavier. Therefore you only need 1 use of the see saw, and that is to measure the person who weighs differently with one of the other 11, therefore working out whether he is lighter or heavier depending on which way the scales tip, as the riddle asks.

Ediz Chakarto

This is the correct, simplest solution

Søren Hougaard Rasmussen

This is a very famous math puzzle. It is definitely not a trick on words, the clue is that you do need all three uses of the seesaw. Even if it was just a trick, why scoff at a guy who actually solved it no matter which person it is?

J T B

4y↑1

6 + 6, right falls, use they 6 for 2nd try.
3 + 3, right falls, use they 3 for last try.
1 left, 1 middle, 1 right. Whatever way if falls that person is heavier

LifeProjX

4y↑1

J T B that is incorrect

J T B

@LifeProjX how is that incorrect 🤣🤣🤣 thats literally it. I dont see you explaining why its incorrect

LumiNite

4y↑1

@J T B because the person could be heavier OR lighter. You cant tell which one is the guy

LifeProjX

4y↑1

boyf riends is correct. If you do a 6v6 you won’t know whether there is a heavy person on one side or a light person on the other.

GoolmeGaming

Not tryna flex, but I solved this riddle in 10 seconds. I was just curious if this was a joke and the tv show wanted the riddle too be easy or if it actually was hard for some people. I am in the top 2 % tho and a member of mensa, so sometimes I dont know if its hard or easy for the average person.

LifeProjX

definitely took me longer than 10 seconds. any secrets on how you came up with the solution?

GoolmeGaming

@LifeProjX Some riddles just come very easy too me, this one did. I just went into paint and drew somewhat the same of what you showed here.

GoolmeGaming

@LifeProjX My mind explodes with ideas when comming too riddles like these. First I thought I had too start with 6-6 but then I realised immediatly that it had too be 4-4 because no matter the outcome then, if its center or right or left, you end up with 4 people and from there I already knew the answear too the rest.

Justin Buergi

This really didn’t seem that hard to me. Took me 5 minutes to solve and was so surprised by how easy it was that I wrote it out and double checked my worked. Kinda disappointed in captain holt.

Josh Temple

5y↑1

Put 6 vs 6 on the seesaw. The heavier side has the heavier person.

Now split that group and do 3 vs 3. Again, the heavier group has the heavier person.

Put two of the people from that group back on the seesaw.

Either you’ll see the heavier person weigh down their side or the two will be equal and you know it’s the person not on the seesaw.

LifeProjX

5y↑4

Josh Temple you don’t know that that person is heavy, they might be light. Doing 6v6 doesn’t let you know if the person is heavy on the right of light on the left.

Ghost Rider

Excellent bro

LifeProjX

Thanks!

Sgt Pluck

46w

Clear as mud. Don't understand that at all. Why is 11 (or any other one number) weighed only once. Why he is not heavy? There's a CRC as well as a CLC...

UnluckyGambler

4y↑1

i worked out this myself in 10 mins. booyah.

LifeProjX

thats better than me!

Tomáš Staňa

It is not that difficult puzzle, wonder why no one there solved it ...

Dennis Cholo

yeah but why would you pick the second set of numbers? or the third set? are they just random numbers?

LifeProjX

No I made an algorithm. I've been planning on making a video about it but haven't got around to it. its pretty cool tho. Ill try and make the video soon.

Natalie Fiset m.d.

You have a great mind!😀

LifeProjX

Thank You!

Duzzixx :

But how do you know if the person is lighter or heavier, Holt doesent say if hes heavier or lighter

SirHoneyBadger

You might of figured it out but if you're still curious.

Take person 11 for example. The seesaw can either go CRC or CLC. The way the seesaw tilts is dependent on whether or not the person is heavier or lighter, it'll always tilt to the heavier side. So all you would have to do is observe what happens. If the seesaw goes 'CRC' then you know that person 11 is heavier since the seesaw tilted to the right, where person 11 is. This means you can tell who is the odd one out and also whether or not they're heavier or lighter. Hope this helps.