Fall
w.clouds Lyrics
Jump to: Overall Meaning ↴ Line by Line Meaning ↴
When I see you now I get sad
I thought I was supposed to love you
Throughout the good and the bad
But I can't help that things have turned out this way
I've tried so long and so hard
But when I look into the eyes of a stranger
Who's supposed to be my lover, everything falls apart
Let me go
And when we're lying down together
I feel I lie there as a log
I wonder if you can see that I'm not here
And ask myself if I was even there all along
Let me go
Let me go
The lyrics of w.clouds's song "fall" describe the struggles of someone who seeks approval and validation from others. The person is desperate to behave well and for others to acknowledge their efforts. They wait for days, hoping to hear their name being called out in appreciation, but it never happens. They aspire to be like someone they admire, someone who seems to have it all together. They seek guidance and direction, hoping to figure out the right things to do to be accepted and validated.
This song reflects how many people feel in their lives. Everyone at some point struggles with feeling like they are not enough, wondering if they are doing the right things, and hoping to be accepted by others. The lyrics touch on the idea of comparison, where people tend to perceive others as better than themselves when in reality, no one is perfect. By expressing these feelings, the song encourages acceptance and compassion.
One interesting fact about this song is that it features w.clouds's signature vocal style of combining singing and rapping. Another fact is that the song was released as part of an EP called "this is my life," which also includes other tracks that touch on themes of self-discovery and self-acceptance. The EP was produced by the Canadian music collective, The Lost Boys. The song has received positive reviews, with many listeners praising w.clouds's ability to connect emotionally with his audience.
Line by Line Meaning
Permission to behave,
Acknowledgment to act on your own accord,
You know you're not the same
You realize that you don't fit the mold,
You wait for days and days
You patiently wait for recognition,
To hear them say your name
To receive affirmation from the ones you admire,
I wanna be like you
I aspire to embody your qualities,
I think you know the truth
I believe that you possess the knowledge I need,
I wanna be like you
I yearn to emulate your actions and demeanor,
Show me what I should do.
Enlighten me with your guidance and direction,
Nothing left for you to use
You have exhausted all your resources,
Lyrics © DistroKid
Written by: Haley Fish
Lyrics Licensed & Provided by LyricFind
Galv140577
I don't mean to be rude, to ridicule, disrespect, or offend you, I am just a factory worker, not a scientist, but to me the notion of clouds being less dense than the air beneath them, as the only reason why they don't fall, leaves so many questions unanswered that in my opinion it cannot be correct.
Why do cumulus cloud types have the flat-bottom appearence? Why does it not rain continuously? Why so many wildy varying different types of clouds? Why tornadoes, lightening, fog, and all kinds of weather phenomena occur? [rhetorical questions]
I would like to do an experiment to disprove the "less dense than the air beneath" assertion.
Given that water is 800 times more dense than air, the density of a cloud should be about twice that of the air with no cloud in it at the same altitude, temperature and pressure. I would like to do an experiment to prove this using a hot air balloon and some sort of containers to capture some cloud material in one container and then the exact same volume of cloud-free air from the same altitude, pressure, and temperature in an identical container in order to prove than once you get back down to ground level and weigh the two containers, the one with the cloud in it should weigh about twice as much as the other.
Here is the mathematical reason:
Take 1 Km^3 of air at 7,000 feet. (Average height of cumulus clouds) At that height the density is about 80% of the density of air at sea level which is 1.225 Kg/M^3. 1 Km^3 is 1,000 * 1,000 * 1,000 M^3. At 7,000 feet 1 Km^3 of air weighs 1.225 * 0.8 * 1,000,000,000 = 980,000,000 Kg or 980,000 tonnes. Now if you pretend you can do science by looking up stuff on google and ask how big is a typical cloud, it says 1 Km^3, but then you ask how much a typical cloud weighs you get 500,000 Kg or 500 tonnes, but you already know 1 Km^3 of air at typical cloud altitude weighs 2 thousand times more than that. Water vapour is only a trace gas. At typical 60% relative humidity, the percentage of the mass of ambient air that is water vapor is 0.25% of the total mass. A typical 1 Km^3 of air at 7000 feet on an average day contains 980,000 * 0.0025 = 2,450 tonnes of H2O and that is in a volume of air the size of a cloud but with no cloud in it. To turn that volume of air into a cloud you would have to get the water vapour to begin to condense into tiny droplets of liquid water. The white fluffy appearance of a cloud is due to the tiny water droplets scattering the light. At 7000 feet the temperature is around 1 degree C so it is probably going to be icey. For the water vapor to condense it has to have something to condense onto. Each water droplet in a cloud has a spec of dust in it. The 2,450 tonnes of liquid/ice H2O in 1 Km^3 of air in a cloud has decreased in volume by a factor of 1,600. That is the difference in density between water vapour and liquid water. Water density = 1000Kg/M^3. Air density = 1.225Kg/M^3. Water is about 800 times more dense than air so why doesn't it fall?
The acceleration due to Earth gravity is 9.8m/s/s. The terminal velocity of a large raindrop is about 10 m/s or 20 mph. The smaller the raindrop the lower the terminal velocity. This means that when water vapor condenses to form clouds and the size of each droplet is very small the terminal velocity is very slow. Cloud droplets are 10 to 1000 times smaller than rain drops. When you plug the mass, cross-sectional area, drag co-efficient and density of cloud droplets in the formula for calculating terminal velocity you get very close to the droplet not being able to fall at all. Look up "earth's atmospheric electric field" on google, you'll find that near the ground it's 100 V/m. Now consider the fact that each water molecule has an electric dipole moment of 1.85 D. Let's see if you can model how water molecules will interact with each other in droplets/crystals which are around 1 to 100 microns in diameter given that they form six-sided symetrical "snowflake" formations when they freeze, and at the same time model how they will interact with the Earth's atmospheric electric field...?
What I think you should get is clouds that are in fact MORE dense than the air around them at the same altitude/pressure/temperature given the difference in volume of the water droplets compared to the water vapor in the surrounding air (factor of 1,600 difference per 0.25% of the total mass of the air/cloud) but they don't fall because the collective dipole moment of each H2O droplet/crystal given the 1.85 D of each molecule interacts with the Earth's atmospheric electric field 100 V/m in such a way as to cancel out the very small terminal velocity of each droplet/crystal so that the clouds actually do in fact rest on the Earth's atmospheric electric field. They continue to rest in this manner until enough vapor condenses onto each droplet/ice-crystal to make it heavy enough to overcome the electric field repulsion and then reach terminal velocity.
To summarise my hypothesis, it's because of the electric field, while the density only plays a partial role.
Mr Scientific
5 Most Dangerous Dinosaurs Ever Lived on Earth!
Watch Here👉 https://youtube.com/watch?v=412I9qLrPXY
eren
they were da real gaint human beings on earth not dinosaurs..ALLAH DESTROYED DEM CUZ THEY USE TO PLUCK DA TREES FROM ONE HAND...
(Makeryellow)
It's like the Voices in WHAT IF videos :)
Galv140577
I don't mean to be rude, to ridicule, disrespect, or offend you, I am just a factory worker, not a scientist, but to me the notion of clouds being less dense than the air beneath them, as the only reason why they don't fall, leaves so many questions unanswered that in my opinion it cannot be correct.
Why do cumulus cloud types have the flat-bottom appearence? Why does it not rain continuously? Why so many wildy varying different types of clouds? Why tornadoes, lightening, fog, and all kinds of weather phenomena occur? [rhetorical questions]
I would like to do an experiment to disprove the "less dense than the air beneath" assertion.
Given that water is 800 times more dense than air, the density of a cloud should be about twice that of the air with no cloud in it at the same altitude, temperature and pressure. I would like to do an experiment to prove this using a hot air balloon and some sort of containers to capture some cloud material in one container and then the exact same volume of cloud-free air from the same altitude, pressure, and temperature in an identical container in order to prove than once you get back down to ground level and weigh the two containers, the one with the cloud in it should weigh about twice as much as the other.
Here is the mathematical reason:
Take 1 Km^3 of air at 7,000 feet. (Average height of cumulus clouds) At that height the density is about 80% of the density of air at sea level which is 1.225 Kg/M^3. 1 Km^3 is 1,000 * 1,000 * 1,000 M^3. At 7,000 feet 1 Km^3 of air weighs 1.225 * 0.8 * 1,000,000,000 = 980,000,000 Kg or 980,000 tonnes. Now if you pretend you can do science by looking up stuff on google and ask how big is a typical cloud, it says 1 Km^3, but then you ask how much a typical cloud weighs you get 500,000 Kg or 500 tonnes, but you already know 1 Km^3 of air at typical cloud altitude weighs 2 thousand times more than that. Water vapour is only a trace gas. At typical 60% relative humidity, the percentage of the mass of ambient air that is water vapor is 0.25% of the total mass. A typical 1 Km^3 of air at 7000 feet on an average day contains 980,000 * 0.0025 = 2,450 tonnes of H2O and that is in a volume of air the size of a cloud but with no cloud in it. To turn that volume of air into a cloud you would have to get the water vapour to begin to condense into tiny droplets of liquid water. The white fluffy appearance of a cloud is due to the tiny water droplets scattering the light. At 7000 feet the temperature is around 1 degree C so it is probably going to be icey. For the water vapor to condense it has to have something to condense onto. Each water droplet in a cloud has a spec of dust in it. The 2,450 tonnes of liquid/ice H2O in 1 Km^3 of air in a cloud has decreased in volume by a factor of 1,600. That is the difference in density between water vapour and liquid water. Water density = 1000Kg/M^3. Air density = 1.225Kg/M^3. Water is about 800 times more dense than air so why doesn't it fall?
The acceleration due to Earth gravity is 9.8m/s/s. The terminal velocity of a large raindrop is about 10 m/s or 20 mph. The smaller the raindrop the lower the terminal velocity. This means that when water vapor condenses to form clouds and the size of each droplet is very small the terminal velocity is very slow. Cloud droplets are 10 to 1000 times smaller than rain drops. When you plug the mass, cross-sectional area, drag co-efficient and density of cloud droplets in the formula for calculating terminal velocity you get very close to the droplet not being able to fall at all. Look up "earth's atmospheric electric field" on google, you'll find that near the ground it's 100 V/m. Now consider the fact that each water molecule has an electric dipole moment of 1.85 D. Let's see if you can model how water molecules will interact with each other in droplets/crystals which are around 1 to 100 microns in diameter given that they form six-sided symetrical "snowflake" formations when they freeze, and at the same time model how they will interact with the Earth's atmospheric electric field...?
What I think you should get is clouds that are in fact MORE dense than the air around them at the same altitude/pressure/temperature given the difference in volume of the water droplets compared to the water vapor in the surrounding air (factor of 1,600 difference per 0.25% of the total mass of the air/cloud) but they don't fall because the collective dipole moment of each H2O droplet/crystal given the 1.85 D of each molecule interacts with the Earth's atmospheric electric field 100 V/m in such a way as to cancel out the very small terminal velocity of each droplet/crystal so that the clouds actually do in fact rest on the Earth's atmospheric electric field. They continue to rest in this manner until enough vapor condenses onto each droplet/ice-crystal to make it heavy enough to overcome the electric field repulsion and then reach terminal velocity.
To summarise my hypothesis, it's because of the electric field, while the density only plays a partial role.
Bagazu
@ANALATOR 420 idi** it's his second channel.
SSB Goku
Is this your voice
мιʀᴀz
clouds can weigh more than a million pounds, and a vivacious thunderstorm can pack billions if not trillions of pounds of water in one tiny part of the sky
Velinix
I find so much information with Mr Scientific. You are amazing
Lev Kotlyarov
Next video: "Why doesn't our atmosphere fall due to gravity?"
PancakeEpic Minecraft101
imagine if a storm cloud touched the surface it would be literall scary